Solving Quadratic Equations
An Example Of A Math Lesson In English |
(A
quadratic equation is a polynomial equation of degree two. The
standard form
is ax2 + bx + c = 0.)
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Ok.. There are
primarily three types of factoring: |
|
*Common Monomial |
ab + ac = a(b
+ c) |
*Difference of Squares |
x2 - 9 = (x
+3)(x - 3) |
*Quadratic Trinomial |
x2 - 5x + 6 = (x
- 3)(x - 2) |
If you can factor, you
will be able to solve factorable quadratic equations. Let's see how it
is done.
Solve for
x:
Here are the steps you should follow:
Solve for
x: x2 + 3x = 0
Factor the common monomial. |
x(x + 3)=0 |
Set each factor equal to 0 and solve for
x. |
x = 0 |
|
x
+ 3 = 0 x = -3 |
List
all values of x. |
x = {0, -3} |
Solve for
y: y 2 = 16
Get
all terms on the same side. |
y 2 - 16 = 0 |
Factor the difference of squares. |
(y + 4)(y - 4) =0 |
Set each factor equal to 0 and solve for
y. |
y + 4 =
0 y = -4 |
|
y
- 4 = 0 y = 4 |
List
all values of y. |
y = {-4, 4} |
Solve for
c: c 2 - 12 = c
Get
all terms on the same side. |
c 2 - 12 - c
=0 |
Arrange the terms in standard form. |
c 2 - c -
12 = 0 |
Factor the quadratic trinomial. |
(c + 3)(c - 4) = 0 |
Set each factor equal to 0 and solve for
c. |
c + 3 =
0 c = -3 |
|
c
- 4 = 0 c = 4 |
List
all values of c. |
c
= {-3, 4} |
Solve for
x:
Employ "product of the means = product of the
extremes" (cross-multiply) for this proportion. |
|
Get
all terms on the same side. |
x
2 - 1296 = 0 |
Factor the difference of squares. |
(x
+ 36)(x - 36) =0 |
Set each factor equal to 0 and solve for
x. |
x + 36 = 0
x = -36 |
|
x - 36 = 0
x = 36 |
List
all values of x. |
x = {-36, 36} |
Solve for
x:
Write a quadratic
equation, in the form ax2 + bx + c =
0, whose roots are 2 and 5.
The
simplest answer will be an equation where the factors of the
expression are (x - 2) and (x - 5). Create this
equation. |
(x - 2)(x - 5) =
0 |
Multiply. |
x
2 - 5x - 2x + 10 = 0 |
Combine to get an
answer equation. |
x 2 - 7x + 10 = 0 |
The square of a number
exceeds 5 times the number by 24. Find the number(s).
Translate the problem into a mathematical
equation. |
x2 = 5x + 24 |
Get
all terms on the same side. |
x
2 - 5x - 24 = 0 |
Factor the difference of squares. |
(x - 8)(x + 3) =0 |
Set each factor equal to 0 and solve for
x. |
x - 8 = 0
x = 8 |
|
x + 3 = 0
x = -3 |
List
all values of x. |
x = {8, -3} |
In football, the height
of the football reached during a pass can be modeled by the equation
h = -16t 2 + 28t + 6, where the height,
h, is in feet and the time, t, is in seconds. How long
does it take for this ball to reach a height of 12 feet?
Substitute 12 into the equation for
h. |
12 = -16t 2 + 28t +
6 |
Get
all terms on the same side. Move terms to the left side to avoid
working with a negative leading coefficient. |
16t 2 - 28t + 6 = 0 |
Factor the quadratic trinomial. |
(4t - 1)(4t - 6) =0 |
Set each factor equal to 0 and solve for
t. |
4t - 1 = 0
4t = 1 t = 1/4 |
|
4t - 6 = 0 4t = 6 t
= 6/4=3/2 |
List
all values of t that are positive. Negative time, should it
appear, is not considered an answer. |
t = {1/4, 3/2}. Reaches a height of 12 feet when time is 0.25
seconds (ball going up) and 1.5 seconds (ball coming down). |
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